10 lines
426 B
Lua
10 lines
426 B
Lua
return function(sec)
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local hours = math.floor(sec/3600)
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local minutes = math.floor((sec - hours*3600)/60)
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local seconds = sec - (hours*3600) - (minutes*60)
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hours = ((hours < 10) and ("0"..hours)) or hours
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minutes = ((minutes < 10) and ("0"..minutes)) or minutes
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seconds = ((seconds < 10) and ("0"..seconds)) or seconds
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return ((tonumber(hours) > 0 and hours..":") or "")..minutes..":"..seconds
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end
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